A manufacturing plant produces a batch of 10 containers out of which 4 are defective. in a quality inspection test, 3 containers are chosen at random. what is the probability that at least one would be defective
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Total number of containers = 10
Total number of defective containers = 4
Find the number of non-defective containers:
Total number of non-defective container = 10 - 4 = 6
Find the probability that none of the 3 are defective:
P(none of the 3 chosen are defective) = (6/10)(5/11)(4/10) = 6/55
Find the probability that at least 1 is defective:
Probability that at least 1 is defective = 1 - none is defective
Probability that at least 1 is defective = 1 - 6/55 = 49/55
Answer: The probability is 49/55
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