A manufaturer has 600 litres of a 12% solution of acid.How many litres of a 30% acid solution must be added to it so that acid content in the resulting mixture will be more than 15% but less than 18%
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Let x litres of 30% acid solution is required to be added. Then
Total mixture = (x + 600) litres
Therefore
30% x + 12% of 600 > 15% of (x + 600)
and 30% x + 12% of 600 < 18% of (x + 600)
or 30x100+12100(600)>15100(x+600)and
30x100+12100(600)<18100(x+600)or
30x+7200>15x+9000
and
30 x +7200<18x+10800
or
15x>1800 and 12x<3600or x >120
and x<300
So 120<x<300
Thus the number of liter of 30% solution of acid will have to be more than 120 litres but less than 300 litres......
Let x litres of 30% acid solution is required to be added. Then
Total mixture = (x + 600) litres
Therefore
30% x + 12% of 600 > 15% of (x + 600)
and 30% x + 12% of 600 < 18% of (x + 600)
or 30x100+12100(600)>15100(x+600)and
30x100+12100(600)<18100(x+600)or
30x+7200>15x+9000
and
30 x +7200<18x+10800
or
15x>1800 and 12x<3600or x >120
and x<300
So 120<x<300
Thus the number of liter of 30% solution of acid will have to be more than 120 litres but less than 300 litres......
piyushsingh0:
heheh
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