Question

a marble 100g drop from the tower and come to at rest find change in momentum
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Answer 1

ANSWER

Impulse act = 2mVcosθ/marble

where V = velocity of marbles before collision with surface.

V=2×g×h=2×10×9.8g=9.8m/s2

     = 14

For one second total impulse on the surface = No. of marbles falling per second × each marble impulse

                                                                           = 50×2×m×Vcosθ

                                                                           = 100×1×10−3×1.4×cosθ

                                                                           = 1.4cosθ

impulse = f.t           t = 1sec       F = 1.4cosθ

(I) for θ=00            (II) for θ=600F=0.7N

          F = 1.4N