Question

a marble 100g dropped from top of a tower of height 5m and comes to rest when it hit the ground. the change in momentum in kg m/s of the marbel when it hit the groud is
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Answer 1

The time taken by the body to fall from the height h is

t=

g

2h

....................................(1)

After the first rebound, time taken to rise to height h

1

and coming back is

t

1

=2

g

2h

1

t

1

=2

g

2e

2

h

t

1

=2e

g

2h

Time taken in rising to height h

1

and coming back is

t

2

=2e

2

g

2h

Time taken by the body in coming to rest

t

3

=

g

2h

+2e

g

2h

+2e

2

g

2h

t

3

=

g

2h

+2e

g

2h

[1+e+e

2

+−−−−−−−−−−.]

t

3

=

g

2h

+2e

g

2h

[

1−e

1

]

t

3

=

g

2h

[1+

1−e

2e

]

t

3

=

g

2h

[

1−e

1−e+2e

]

t

3

=

g

2h

[

1−e

1+e

]

t

3

=t[

1−e

1+e

]........................from (1)

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Answer 2

Answer:

x=1

Explanation:

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