A marble block of mass 2kg lying on ice when a velocity of 6m/s is stopped by Friction in 10s . then , the coefficient of Friction is [AIEEE 2003,]
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- Explanation:- Let coefficient of Friction be μ ,then retardation will be μg. from Equation of motion ,
- ⟹v = u + at
- ⟹0 = 6- μg
- ⟹μ = 6/100 = 0.06 Answer
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