Question

A marble dropped from a bridge and strike the water in 5.0s. Calculate the speed with which it strikes

Answer 1

Answer:

Explanation:

Use equation of motion

S

=

ut

+

1

2

at

2

Where

S =

Displacement covered

u =

Initial velocity

a =

Acceleration (It’s

9.8 m/s

2

due to Earths gravity)

t =

Time taken to cover displacement

S

Marble is dropped. It means initial velocity (

u

) of marble is

0

Therefore the equation becomes

S

=

1

2

at

2

S

=

1

2

×

9.8 m/s

2

×

(5 s)

2

S

=

122.5

m

Displacement covered by the marble when thrown from the bridge is obviously height of the bridge.