A marble is dropped from the top of a tower. What distance does it fall after 3s of
dropping? (g=9.8m/
a) 44.1m b)14.2m c) 22.4m d) 42.4m
Answers
Answered by
9
Answer:
Distance travelled by the marble = 44.1m
Or the option (a) is correct .
Step-by-step explanation:
Given :
Time = 3s
Acceleration due to gravity = 9.8m/s²
Initial velocity = 0 m/s
To find :
The distance travelled by marble while falling down
Formula used :
Using the second equation of motion -:
Where,
s = Distance
u = Initial velocity
t = Time
a = Acceleration due to gravity
Solution :
So , the distance travelled by the marble is 44.1m .
Extra information :
First equation of motion -:
Where,
u = Initial velocity
v = Final velocity
a = Acceleration
t = Time
Third equation of motion -:
Where,
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
Answered by
0
Answer:
Marble is dropped from a top of a tower, what distance does it fall after 3 second of dropping. find
its velocity at this point
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