A marble of mass 20 g is moving to the right at 4 m/s when it collides with a smaller, stationary marble of mass 8 g. The smaller marble moves off to the right at 5 m/s. With what velocity (magnitude and direction) does the first marble move after the collision?
Answers
Answered by
1
Using Momentum Conservation:
⇒m
1
u
1
+m
2
u
2
=m
1
v
1
+m
2
v
2
⇒1(21)+2(−4)=1(1)+2v
2
⇒v
2
=6m/s
Coefficient of Restitution:
e=
u
1
−u
2
v
2
−v
1
=
21+4
6−1
=0.2
Kinetic Energy lost:
=
2
1
m
1
(v
1
2
−u
1
2
)+
2
1
m
2
(v
2
2
−u
2
2
)
=
2
1
1(1−441)+
2
1
2(36−16)
=−200J
Impulse of Force:
I=(Δmv)
1
=1(1−21)=−20
=(Δmv)
2
=2(6−(−4))=20
Similar questions