Question

A marble of mass is dropped from a height h on a hard floor . If is rebounds to the same height , the change in momentum of marble is

Answer 1

Taking rebound velocity(v) as positive

Untill the ball hits the ground..

p(initial)=m.(-v)

When bouncing back..

p(final)= m.(v)

p(change)=p(final)-p(initial)

p(change)=mv-(-mv)

p(change)=2mv

Hence,change in momentum is equall to 2 times its initial momentum

hope this will help you :-))