Question

A marble of mass 'm' is dropped from a height 'h' on a hard floor . If it rebounds to the same height, the change in momentum of marble is

Answer 1

The marble is dropped from heighththen the velocity of the marble on reaching the ground is

2gh

Since it is given that it rebounds to the same height after striking the ground

Hence the change in velocity will be given as

Δv=

2gh

−(−

2gh

)

Hence the change is velocity is2

2gh

The change is momentum becomes

2m

2gh

Explanation:

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