A marble of mass 'm' is dropped from a height 'h' on a hard floor. If it rebounds to the same height, the
change in momentum of marble is
Answers
Answered by
1
Answer:
2Mv or 2 times the intial momentum
Explanation:
change in momentum = final p - intial p
Intial p = mv
final p = -mv ( as momentum is a vector quantity ) and here it's direction has reversed that's why i took negative
hence change is P = 2mv
Similar questions