A marble of mass ‘m’ is dropped from a height ‘h’ on a hard floor.If it rebounds to the same height change in momentum of marble is.
a) m√2gh in downward direction. b)m√2gh in upward direction.
c)2m√2gh in downward direction. d)2m√2gh in upward direction
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Answer: The marble is dropped from heighththen the velocity of the marble on reaching the ground is
2gh
Since it is given that it rebounds to the same height after striking the ground
Hence the change in velocity will be given as
Δv=
2gh
−(−
2gh
)
Hence the change is velocity is2
2gh
The change is momentum becomes
2m
2gh
Explanation:
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