Question

a marble of mass m is moving inside frictionless cone of Semivertical angle theta. if path of marble is rotated in a horizontal plane and it's speed is V, then radius of circular path is​

Answer 1

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Answer 2

Answer:

Given =  mass = m

              angle = θ

              speed = V

to find =  radius

solution =

             ⇔ apply the formula

           ⇔     F = mv²/ r

             ⇔ centripetal accelaration = ac = F/M

             ⇔ ac = mv²/r/m

             ⇔ac = v²/r

             ⇔  r =  ac / v²...(ac = F/m)

radius of circular path is​   r =  ac / v²