Question

A marble rolling on a smooth floor has an initial velocity of 0.4m/s. If the floor offers retardation of 0.02m/s^2, calculate the time it will take to come rest.​

Answer 1

Answer:

The initial velocity of marble is 0.4m/s.

And the retardation is 0.2m/s²,or a=-0.2m/s²

Now by first equation of motion

v=u+at

where u is initial velocity,v is final velocity a is acceleration and t is time.

Putting the values in the equation,we get

0=0.4+(-0.2)t. (final velocity is 0 because body comes to rest.)

or,0.2t=0.4

or,t=0.4/0.2=2s

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