A marble rolling on a smooth floor has an initial velocity of 0.4 m/s. If the floor offers a retardation of 0.02 m/s2, calculate the time it will take to come to rest.
Answers
Answered by
12
Answer:
The initial velocity of marble is 0.4m/s.
And the retardation is 0.2m/s²,or a=-0.2m/s²
Now by first equation of motion
v=u+at
where u is initial velocity,v is final velocity a is acceleration and t is time.
Putting the values in the equation,we get
0=0.4+(-0.2)t. (final velocity is 0 because body comes to rest.)
or,0.2t=0.4
or,t=0.4/0.2=2s
Explanation:
hope this helps
Similar questions
English,
4 months ago
Science,
4 months ago
English,
4 months ago
Math,
8 months ago
Environmental Sciences,
8 months ago
Math,
11 months ago
Computer Science,
11 months ago