A marble rolling on a smooth floor has an initial velocity of 0.4m/s .if the floor offer a retardation of 0.02 m/s,calculate the time it will take to come at rest
Answers
Answered by
25
Initial velocity (u) = 0.4 m/s
Acceleration (a) = - 0.02 m/s²
Final velocity (v) = 0 m/s. [because, the marble will come to rest .]
Time (t) = ?
Therefore,
Answered by
11
u=0.4
a= -0.02
v=0 (as it comes to rest)
t=?
We will use the v=u+at
0=0.4+0.02(t)
-0.4=0.02(t)
-0.4
------- = t
0.02
t = 20 seconds
a= -0.02
v=0 (as it comes to rest)
t=?
We will use the v=u+at
0=0.4+0.02(t)
-0.4=0.02(t)
-0.4
------- = t
0.02
t = 20 seconds
Similar questions