Question

A marble rolling on a smooth floor has an initial velocity of 0.4 metre per second. If the floor offers a retardation of 0.02 M per second square calculate the time it will take to come to rest

Answer 1

We have initial velocity =0.4,
final velocity =0,
retardation= -0.02.
at=v-u.
that is -0.02×t=0-0.4
= -0.02×t= -0.4
=t= -0.4 by -0.02.
=T=0.2