Question

A marble rolling on a smooth floor initial velocity 0.4m/s. if the floor offers retardation of 0.02 m/s -2, calculate the time it will take to come to rest.

Answer 1

Explanation:

we know that

v = u + at

the time taken will be given as

t = (v - u) / a

given

u = 0.4 m/s

v = 0 (comes to rest)

a = -0.02 m/s2 (retardation)

so,

t = (0 - 0.4) / 0.02

thus,

t = 20s

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Answer 2

Given,  u = 0.4 m/s

v = 0  

a  = -0.02 m/s2  

v = u + at

so, t = (0 - 0.4) / 0.02

Thus, t = 20s