a marble tile measures 15 cm × 20 cm how many tiles will be required to cover a Wall of size 4m × 6 m
Answers
Answered by
9
Answer: 800 tiles
Step-by-step explanation:Area of the wall=4 m×6 m=24 m^2=240000 cm^2
Area of each tile=20 cm×15 cm=300 cm^2
Required number of tiles=Area of wall÷Area of each tile
=240000÷300=800
ZunayedTIME:
Plz mark as Brainliest...please PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE
Answered by
8
Here, we have that,
One marble tile = 15 * 20 = 300 cm2.
Size of the wall = 4 * 6 = 24 m2. = 240000 cm2
Since, 1 m2 = 10000 cm2.
So, no. Of tiles required = (240000) / 300 = 800 tiles.
Hence, 800 tiles would be required.
Hope this helps,.
If helps, please mark it as brainliest ^_^
Similar questions