Question

A marble tile measures 16cm×20cm . How many tiles will be required to cover a wall of size 4m×5m?​

Answer 1

Answer :

• 62.5 tiles will be required to cover a wall of size 4m × 5m.

Given :

• A marble tiles measures 16cm × 20cm

To find :

• How many tiles will be required to cover a wall of size 4m × 5m

Solution :

Given,

• 16cm × 20cm
• 4m × 5m

We know that,

• Number of tiles = Area of marble ball / Area of marble tile

Where,

• Area of marble ball is 4m × 5m = 400 × 500
• Area of marble tile = 16 × 20

↝ Number of tiles = Area of marble ball/Area of marble tile

↝400 × 500 / 16 × 20

↝ 200000/320

↝ 62.5

Hence , 62.5 tiles will be required to cover a wall of size 4m × 5m.

Answer 2

❍ Given :-

A marble tile measures 16cm×20cm.

$\:$

❍ To find :-

How many tiles will be required to cover a wall of size 4m×5m?

$\:$

❍ Used formula :-

$\red \star \: \boxed{ \displaystyle \sf Number \: of \: tiles = \frac{Area \: of \: marble \: ball}{Area \: of \: marble \: tile} }$

$\:$

❍ Solution :-

First, we have to convert 4m×5m into cm

1m = 100cm

4m = ?

$\sf \underline{By \: the \: Cross \: Multiplication}$

$⟶ \: \displaystyle \sf\frac{100×4}{1} = 400cm$

And,

1m = 100cm

5m = ?

$\sf \underline{By \: the \: Cross \: Multiplication} \:$

$⟶ \: \displaystyle \sf\frac{100×5}{1} = 500cm$

400cm×500cm

Here,

$⟹ \: \displaystyle \sf Number \: of \: tiles = \frac{Area \: of \: marble \: ball}{Area \: of \: marble \: tile}$

$⟹ \: \displaystyle \sf Number \: of \: tiles = \frac{400cm \times 500cm}{16cm \times 20cm}$

$⟹ \: \displaystyle \sf Number \: of \: tiles = \frac{200000cm}{320cm}$

$⟹ \: \displaystyle \sf Number \: of \: tiles = \large \frac{ \cancel{200000} \: ^{ \cancel{12500} \: ^{ \cancel{1250} \: ^{625} } } } { \cancel{320} \: _ { \cancel{20} \: _{ \cancel{2} \: _1} }} \:$

$⟹ \: \displaystyle \sf Number \: of \: tiles = 625cm$

In centimeters,

625cm

In meters,

62.5 in meters

Hence, 62.5m or 625cm tiles will be required to cover a wall of size 4m×5m