A marble tile measures 20 cm x 25 cm. How many tiles will be required to cover a wall of size of
5m by 2 m?
Answers
Answer:
200 tile.
Step-by-step explanation:
length of tile=25cm=0.25 m
breadth of tile=20 cm = 0.2 m
area of tile= 0.25×0.2=0.05 m^2
area of wall =5×2=10 m^2
no. of tile required to cover wall = area of wall/area of tile.
= 10/0.05
=200 tile.
______@Deepak Razput
Answer:
200 tiles will be required to cover a wall of size of 5m by 2 m
Step-by-step explanation:
Length of tile= 20 cm
breadth of height= 25 cm
Therefore, the area of the tile= length × breadth
= 20 × 25 cm²
= 500 cm²
Now, length of the wall= 5 m
breadth of the wall= 2 m
Therefore, area of the wall= length × breadth
=5 × 2 m²
= 10 m²
Since 1 m= 100 cm
1 m²= 100 × 100= 10000 cm²
Therefore, area of wall in cm= 10 × 10000 cm²
= 100000 cm²
Now, number of tiles= area of wall ÷ area of tiles
= 100000÷500
= 200