Math, asked by Anviyede, 4 months ago

A marble tile measures 20 cm x 25 cm. How many tiles will be required to cover a wall of size of
5m by 2 m?

Answers

Answered by deepak33303
1

Answer:

200 tile.

Step-by-step explanation:

length of tile=25cm=0.25 m

breadth of tile=20 cm = 0.2 m

area of tile= 0.25×0.2=0.05 m^2

area of wall =5×2=10 m^2

no. of tile required to cover wall = area of wall/area of tile.

= 10/0.05

=200 tile.

______@Deepak Razput

Answered by totaloverdose10
1

Answer:

200 tiles will be required to cover a wall of size of 5m by 2 m

Step-by-step explanation:

Length of tile= 20 cm

breadth of height= 25 cm

Therefore, the area of the tile= length × breadth

= 20 × 25 cm²

= 500 cm²

Now, length of the wall= 5 m

breadth of the wall= 2 m

Therefore, area of the wall= length × breadth

=5 × 2 m²

= 10 m²

Since 1 m= 100 cm

1 m²= 100 × 100= 10000 cm²

Therefore, area of wall in cm= 10 × 10000 cm²

= 100000 cm²

Now, number of tiles= area of wall ÷ area of tiles

= 100000÷500

= 200

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