Question

a marble title measures 12cm ✖ 10cm. how many titles required to cover a wall 8 metre long and 2 metre broad? also find total cost of tiles at RS. 40 per tile
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Answer 1

Correct Question-:

• A marble tile measures 12cm ✖ 10cm. how many titles required to cover a wall 8 metre long and 2 metre broad ? also, Find total cost of tiles at RS. 40 per tile ?

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{  Total\:cost \:of\:tiles \:\: =  Rs.53,333.333[ Approx]}}}}}$

Explanation-:

$\frak{Given \:\: -:} \begin{cases} \sf{The\:dimensions \:of\:Tiles\:\:are\:= \frak{12cm × 10cm }} & \\\\ \sf{Length \:of\:wall \:is \:=\:\frak{8}}& \\\\ \sf{Breadth \:of\:wall\:is= \frak{2 m }} & \\\\ \sf{The\:cost\:of\:one\:tile\:is \: = \frak{Rs.40 per tile }} \end{cases}$

$\frak{To\:Find\: -:} \begin{cases} \sf{The\:total \:cost\: of \:tiles\: at \:Rs.\: 40 \:per \:tile.} \end{cases}$

Analysing-:

• By Analysing the given things -:
• 1 . We can see that the tiles is in Rectangular form .
• 2 . The length of tile is 12 cm and breadth of tile is 10 cm .
• 3 . We can see that wall is also in Rectangular form .
• 4. The length of wall is 8 metre and breadth of wall is 2 metre .

Now ,

• We know that [ 1m = 100 cm ]
• Then ,
• The length of wall is 8 m = 800 cm
• The breadth of wall is 2m = 200 cm

Now ,

• $\underline{\boxed{\star{\sf{\blue{ Area_{(Rectangle)}  \: = \: Length \times Breadth }}}}}$

Here ,

• The length of tile is 12 cm
• The breadth of tile is 10 cm

Now ,

• $\implies{\sf{\large{Area_{Tile} = 12 × 10 }}}$
• $\implies{\sf{\large {Area_{Tile} = 120cm² }}}$

Therefore,

• $\underline{\boxed{\star{\sf{\blue{  Area \:of\:Rectangular \:tile\: =  120 cm².}}}}}$

Now ,

• $\underline{\boxed{\star{\sf{\blue{ Area_{(Rectangle)}  \: = \: Length \times Breadth }}}}}$

Here ,

• The length of wall is 800 cm
• The breadth of wall is 200 cm

Now ,

• $\implies{\sf{\large{Area_{Wall} = 800 × 200 }}}$
• $\implies{\sf{\large{Area_{Wall} = 160000cm² }}}$

Therefore,

• $\underline{\boxed{\star{\sf{\blue{  Area \:of\:Rectangular \:wall\: =  160000 cm².}}}}}$

Now ,

• No. of tiles = Area of wall / Area of tile .

Here ,

• Area of wall = 160000 cm ²
• Area of tile = 120 cm²

Now ,

• $\implies{\sf{\large{Number_{Tiles} = \frac{160000}{120} }}}$
• $\implies{\sf{\large{Number_{Tiles} = \frac{16000}{12} }}}$
• $\implies{\sf{\large{Number_{Tiles} = \frac{4000}{3} }}}$
• $\implies{\sf{\large{Number_{Tiles} = 1,333.333 [Approx]\:tiles\: are\:needed \:to\:cover\:Rectangular \:wall.}}}$

Therefore,

• $\underline{\boxed{\star{\sf{\blue{  Number \:of\:tiles \:\: =  1333.333[ Approx]}}}}}$

Now ,

• Total cost of Tiles = No. of tiles × The cost of one tile
• Here ,
• No. of tiles = 1333.333[ Approx]
• The cost of one tile = Rs . 40

Now ,

• $\implies{\sf{\large{Total\; cost _{Tile} = 1,333.333 × 40 }}}$
• $\implies{\sf{\large{Total\; cost _{Tile} = Rs. 53,333.333 }}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{  Total\:cost \:of\:tiles \:\: =  Rs.53,333.333[ Approx]}}}}}$

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