A mark is made at the bottom of the beaker and a microscope is focused on it. the microscope is raised through 1.5 cm. to what height must the water be poured to bring the mark into the focus
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The height must the water be poured to bring the mark into the focus is 6 cm.
Given:
Raise of microscope = d = 1.5 cm
Explanation:
Let the height of the water poured in the beaker be 't'
The apparent shift is given by the formula:
d = t × (1 - 1/μ)
Where,
μ = Refractive index of the medium.
Here, the medium is water.
The refractive index of water = 4/3
On substituting the values, we get,
1.5 = t × (1 - 1/(4/3))
1.5 = t × (1 - 3/4)
1.5 = t × ((4 - 3)/4)
1.5 = t × 1/4
t = 1.5 × 4
∴ t = 6 cm
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