Question

A marksman wishes to hit a target just in the same level as the line of sight. How high from the target he should aim, if the distance of the target is 1600m and the muzzle velocity of the gun is 800m/s?

Answer 1

Answer:

Using the Range formula

R = V^2 sin (2 theta) / g

sin (2 theta) = R g / V^2   = 1600 * 9.8 / 800^2 = .0245

2 theta = 1.40 deg

theta = .7 deg

So he should aim .7 deg above the target

h / 1600 = tan theta

h = 1600 * tan .7 = 19.6 m above the target

Answer 2

Answer:

Explanation: Hope it helps u

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