Question

a mason builds 1/7 of a wall each day for 4 days. if he completes the wall in 5 days what part of wall is constructed on the fifth day?​

Answer 1

Answer:

THE PART OF WALL HE CONSTRUCTED ON THE FIFTH DAY IS 3/7

Step-by-step explanation:

ON FIRST DAY HE COMPLETED 1/7 PART OF THE WALL

ON SECOND DAY HE COMPLETED 1/7 PART OF THE WALL

ON THIRD DAY HE COMPLETED 1/7 PART OF THE WALL

ON FOURTH DAY HE COMPLETED 1/7 PART OF THE WALL

THEN TO TOTAL COMPLETED ON 4TH DAY IS

1/7 + 1/7 + 1/7 + 1/7 =  4/7

THEN IF HE COMPLETED FULLY 7/7 ON FIFTH DAY

THEN THE PART OF WALL CONSTRUCTED ON THE FIFTH DAY IS

$\frac{7}{7} - \frac{4}{7} = \frac{3}{7}$

7/7 - 4/7 = 3/7