Question

A mason has to fit a bathroom with a square tiles of the largest possible size. The size of bathroom is 6ft *4ft what would be the size in inches of the tile required that has to be cut and how many such tiles are required?

Answer 1

length of bathroom floor = 6 feet
breadth of bathroom floor = 4 feet
size of one tile = HCF of L and B ²
=2²
total number of tiles = area of floor/area of tile
= ( 6×4 ) ÷ ( 2×2 )
= 24 ÷ 4
= 6
Answer is 6 tiles
hope it helps!

Answer 2

Given:

Size of bathroom = 10 ft. by 8 ft.

= (10 x 12) inch by (8 x 12) inch [conversion from ft. to inch.]

= 120 inch by 96 inch

Now, the largest size of tile required will be the HCF of 120 and 96.

Let's Solve:

So, Applying Euclid’s division lemma

We get,

120 = 96 x 1 + 24

96 = 24 x 4 + 0

⇒ HCF = 24

Thus, we can conclude that the largest size of tile which required is 24 inches

And,

Number of tiles required = (area of bathroom) / (area of a tile)

= (120 x 96) / (24x24)

= 5 x 4

= 20 tiles

Therefore, 20 tiles each of size 24inch by 24inch are required to be cut.