A mason has to fit a bathroom with square marble tiles of the lagrest possible size. The size of the bathroom in 14.5ft by 12.5ft. what would be the size of the tile in inches? How many such tiles are required?
Answers
Answer:
Step-by-step explanation:
Ema bought 360, ₹10 shares paying 12% per annum. She sold them when the price rose to ₹21. She invested the proceeds in ₹5 shares paying 4.5% per annum at ₹3.50 per share. Find the change in her annual income.
Given:
Size of bathroom = 10 ft. by 8 ft.
= (10 x 12) inch by (8 x 12) inch [conversion from ft. to inch.]
= 120 inch by 96 inch
Now, the largest size of tile required will be the HCF of 120 and 96.
Let's Solve:
So, Applying Euclid’s division lemma
We get,
120 = 96 x 1 + 24
96 = 24 x 4 + 0
⇒ HCF = 24
Thus, we can conclude that the largest size of tile which required is 24 inches
And,
Number of tiles required = (area of bathroom) / (area of a tile)
= (120 x 96) / (24x24)
= 5 x 4
= 20 tiles
Therefore, 20 tiles each of size 24inch by 24inch are required to be cut.