Question

A mason has to fit a bathroom with square marble tiles of the largest possible size of bathroom is 10feet and 8feet.what would be the size of tilesin inches? how many such tiles are required?

Answer 1

Size of bathroom = 10ft by 8ft 
= (10 × 12) inch by (8 × 12) inch 
= 120 inch by 96 inch 
The largest size of tile required = HCF of 120 and 96 
By applying Euclid’s division lemma 
120 = 96 × 1 + 24 
96 = 24 × 4 + 0 
∴ HCF = 24 
∴ Largest size of tile required = 24 inches



= 5 × 4 
= 20 tiles

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Answer 2

Given:

Size of bathroom = 10 ft. by 8 ft.

= (10 x 12) inch by (8 x 12) inch [conversion from ft. to inch.]

= 120 inch by 96 inch

Now, the largest size of tile required will be the HCF of 120 and 96.

Let's Solve:

So, Applying Euclid’s division lemma

We get,

120 = 96 x 1 + 24

96 = 24 x 4 + 0

⇒ HCF = 24

Thus, we can conclude that the largest size of tile which required is 24 inches

And,

Number of tiles required = (area of bathroom) / (area of a tile)

= (120 x 96) / (24x24)

= 5 x 4

= 20 tiles

Therefore, 20 tiles each of size 24inch by 24inch are required to be cut.