Question

A mass 0.1kg is rotated in a vertical circle using a string of length 20cms . When the string makes an angle 30 with the vertical, the speed of the mass is 1.5 . The tangential acceleration of the mass at that instant is

Answer 1

Answer:

Tangential acceleration of the object at that instant is

$a_t = 4.9 m/s^2$

Explanation:

Net force on the particle in vertically downwards direction due to its own weight is given as

$F = mg$

now the component of the weight along the tangential direction will exert tangential force on it

so we have

$F_t = mg sin\theta$

now tangential acceleration is given as

$a_t = \frac{F_t}{m}$

$a_t = \frac{mg sin\theta}{m}$

$a_t = g sin\theta$

$a_t = 9.81 sin30$

$a_t = 4.9 m/s^2$

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Topic : Circular motion

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Answer 2

Explanation:

Explanation:

Characteristics of the image form by the plane mirror are:

Since the image form by the plane mirror has magnification is 1 then,

(I). The size of the image form will be the same as the size of the object.

(II). The distance of the image from the mirror will be the same as the distance of the object from the mirror.

(III). The image form will be virtual.

(IV). The image form will be upright.

the position of image related to the position of the object

The image is as far behind the mirror as the object is in front of it i.e, the perpendicular distance of image from the mirror is equal to the perpendicular distance of object from the mirror.