Question

a mass 5 kg is acted upon by a force of 1 n starting from rest how much is distance covered by the mass in 20s?????​

Answer 1

Answer:

Hello mate

Explanation:

Using Newton's second law , F=ma, we get the acceleration to be 0.2m/s

2

.

now we know that s=ut+

2

1

at

2

u=0,t=10s,a=0.2m/s

2

∴s=

2

1

∗0.2∗10

2

=10m

Answer 2

Given :-

• A mass 5 kg is acted upon by a force of 1 n starting from rest

To find :-

• How much is distance covered by the body in 20s?

Solution :-

• Mass of body = 5 kg
• Force acted = 1 N

As we know that

→ Force = Mass + acceleration

→ F = M × a

→ 1 = 5 × a

→ A = 1/5 = 0.2 m/s²

Now,

• Acceleration = 0.2 m/s²

• Initial velocity = 0

• Time = 20s

According to second equation of motion

→ s = ut + ½ at²

Where " s " is distance covered, " u " is initial velocity, " a " is acceleration and " t " is time.

• According to the question

→ s = ut + ½ at²

→ s = 0 × 20 + ½ × 0.2 × (20)²

→ s = 0 + 0.1 × 400

→ s = 40 m

Hence,

• Distance covered i.e 40 m