Physics, asked by piyuroxx380, 9 months ago

A mass 6 kg is suspended by a rope of length 2m from the celling. A force of 50 N in the horizontal direction is applied at the mid-point ‘p’ of the rope as shown in figure. What is the angle the rope makes with the vertical in equilibrium [Take ]. Neglect the mass of the rope.

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Answered by div2007
1

Answer:

A force of 50 N in the horizontal direction is applied at the mid - point P of the rope. as shown. What is the angle the rope makes with the vertical in equilibrium? (Take g = 10 ms-2)

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