Question

A mass attached to a spring when extended by x, its potential energy is U. If extension made 2x, the potential energy will be

a) 2U
b)3U
c)√2U
d) 4U​

Answer 1

Answer:

Explanation:

U = 1/2 K (2)^2 and U ^' = 1/2 K (8)^2 U^'/U = (8/2)^2 = 16 U ^' = 16U