a mass is suspended from the roof of a car by a string while the car has a constant acceleration if the string make an angle of 60° with the vertical if g is equal to 10 M per second square then value of a is
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A Mass is suspended from the roof of a car by a string while the car has a constant acceleration.
Let the acceleration of the car = a Horizontal force on mass = ma Vertical force on the mass = mg
The string makes an angle of 60° with the vertical.
Thus tan 60° = mg/ma
=> √3 = g/a
=> a = g/√3 = 10/√3 m/s^2
Acceleration of car is 10/√3 m/s^2
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Let the acceleration of the car = a Horizontal force on mass = ma Vertical force on the mass = mg
The string makes an angle of 60° with the vertical.
Thus tan 60° = mg/ma
=> √3 = g/a
=> a = g/√3 = 10/√3 m/s^2
Acceleration of car is 10/√3 m/s^2
hope it help you
and follow me
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