Question

A mass m attached to a spring oscillates every 2 sec. If the mass is increased by 2 kg, then time-period increases
by 1 sec. The initial mass is

Answer 1

Answer:

1.6kg

Explanation:

use, T = 2π√(m/k) ---eqⁿ1

T = 2sec and m=?

A/Q,

2+1 = 3 = 2π√{(m+2)/k} ---eqⁿ2

doing , eqⁿ² ÷ eqⁿ1 , then

3/2= √{(m+2)/m}

9/4 = = (m+2)/m

9m = 4m+8

5m = 8

m = 8/5 = 1.6kg.