Physics, asked by babaha32, 1 month ago

A mass M breaks into two pieces in the ratio 1:3 while at rest. If the heavier has a speed of v,
the speed of the lighter is
G.
a) v/3
b) v OCTA
c) 4v
cibe or Cod) 2v

Answer: v/3

Answers

Answered by mithu456
5

Explanation:

Answer = 3v

A mass M break into two pieces in the ratio 1:3 mean

Heavier mass = 3M/4 and velocity =v

Lighter mass =M/4 and assume velocity = v'

Applied momentum conservation

After break both move opposite to each other

Final momentum =initial momentum

(3M/4) v - (M/4) v'=M(0)

v'=3v

Velocity of the lighter mass is 3v

Similar questions