A mass M breaks into two pieces in the ratio 1:3 while at rest. If the heavier has a speed of v,
the speed of the lighter is
G.
a) v/3
b) v OCTA
c) 4v
cibe or Cod) 2v
Answer: v/3
Answers
Answered by
5
Explanation:
Answer = 3v
A mass M break into two pieces in the ratio 1:3 mean
Heavier mass = 3M/4 and velocity =v
Lighter mass =M/4 and assume velocity = v'
Applied momentum conservation
After break both move opposite to each other
Final momentum =initial momentum
(3M/4) v - (M/4) v'=M(0)
v'=3v
Velocity of the lighter mass is 3v
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