Question

A mass m has a force F applied to it as shown

Answer 1

Answer:

Applying newton's law on the system in horizontal directionF=(M+m)a.

Now consider the equilibrium

of block B w.r.t. block M

F2=(mg)2=(mFm+M)2

F2=m2g21−m2(m+M)2,F=mg1−(mm+M)2−−−−−−−−−−−√

Explanation: