Physics, asked by Anonymous, 1 year ago

A mass m is attached to a thin wire and
whirled in a vertical circle. The wire is most
likely to break when

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Answered by Anonymous
7

\huge{\mathfrak{HEYA\:MATE\:!!}}

The wire is most likely to break if mass is at lowest point.

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Answered by Anonymous
6

Hey mate...

here's the answer...

T = mg + mu^2/ l

The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.

Hope this helps❤

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