Physics, asked by madcat375, 6 months ago

A mass 'm' is released, with a horizontal speed v from the top of a smooth and
fixed, hemisphere bowl, of radius r. The angle theta w.r.t. the vertical where it leaves
contact with the bowl is cos-1(v2/3rg+x/3) then the value of x is​

Answers

Answered by aparna6540
1

Answer:

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