Question

A mass m is suspended from a spring of force constant k and just touches another identical spring fixed to the floor the time period of oscillations is

Answer 1

The time period of oscillations is T = π √m / k + π √m /2.k

Explanation:

• When the spring undergoes displacement in the downward direction.
• It completes one half oscillation.
• While it completes another half oscillation in the upward direction.
• Then the total time period is

T = π √m / k + π √m /2.k

Thus the time period of oscillations is T = π √m / k + π √m /2.k

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A cylindrical object of outer diameter 20 cm and mass 2 kg floats in water with its axis vertical. If it is slightly depressed and then released find the time period of the resulting simple harmonic motion of the object. ?

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