Question

A mass m is thrown vertically upward into air with initial speed u. a constant force f due to air resistance acts on the mass during its motion. the maximum distance covered by the mass to reach the top is [take g as acceleration due to gravity]

Answer 1

V²-U²=2as

as at s= Hmax , V=0

during upward motion net acceleration= -(acc. due to air + g)
= -(a+g)

then . - U²= -2(a+g)Hmax.

then H max= U²/2(a+g)