Question

A mass M kg is suspended by a weightless string. thehorizontal force required to hold the mass at 60° with the vertical is

Answer 1

The work done by the force will be equal to the potentail energy gained by the mass.

Let L be the length of the string ,

F.d= MgL (1 -cos45 )

The horizontal displacement of the mass is d= L sin 45

F L sin45 = Mg L(1 - 45)

F = Mg (sq. root 2 - 1)

USE CONSERVATION OF ENERGY

Let x be the force required

T Sin 45=M kg …....1

T Cos45=x ….......2

Divide equation 1 and 2,

1=M/x

x=M

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Answer 2

Answer:

A mass M kg is suspended by a weightless string. The horizontal force required to hold the

mass at 600 with the vertical is Mg squt3

Explanation: