Question

A mass m moves with a velocity v and collides inelastically with another identical mass . After collision , the 1st mass moves with velocity v/√3 in a direction perpendicular to the initial direction of motion . find the speed of the second mass after collision . [AIEEE 2005]​

Answer 1

Answer:

A mass m moves with a velocity v and collides inelastically with another identical mass. After collision the 1st mass moves with velocity 3 v in a direction perpendicular to the initial direction of motion

Answer 2

Explanation:- In x - direction [Before collision]

Apply conservation of momentum , we get

• mu₁ + 0 = mV ₓ
• mv = mvₓ
• vₓ = v

After collision, in y direction , apply conservation of momentum we get

• 0 + 0 = m (v/√3 ) - mvy

• ⟹ vy = v/√3

Velocity of second mass after collision

$v '= \sqrt{ \frac{v}{ \sqrt{3} + } + v {}^{2} } \ \\ \\ = \sqrt{ \frac{4}{3} v {}^{2} } \\ \\ or \: v '\: = \frac{2}{ \sqrt{3} } v \: \: answer \:$