A mass m moving at a speed v and perpendicular to mass M=6m which pivots around a frictionless axle running through its center.it strike and sticks to the end of rod.The moment of inertia of the rod about its center is md2/12.then the angular speed of the system just after collision is
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Answer is 2v/3d
By conservation of angular momentum about pivot.
L=Iω
2
mvd/2 = [Md2/12+m(d/2)^2]ω
= (md^2/2+md^2/4)ω
= 3/4md^2ω = 2v/3d⇒ω
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