Question

A mass M of 20 kg is suspended by two ropes
AC and BC as shown. The tension in the
rope
AC is
1) 20 x 9.8 x 2 N

2) 20 x 9.8 / V3 N

3) 20 x 9.8 x V 3N

4) none
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Answer 1

(2) 20 x 9.8 / √3 N

Given:

• Mass of a mass(M) is 20 kg.
• M is suspended by the two ropes.

To Find:

• The tension in the rope AC.

Solution:

Let's assume that tension in a string is Ta & in a string is b Tb.

​

Now, taking component of the tensions

Ta = sin30∘ =Tbsin30∘ ......(1)

it means Ta =Tb

Ta cos30∘ + Tb cos30∘ = mg   ......(2)

⇒ 2Ta cos30 ∘ = 20×9.8

⇒Ta = Tb

⇒  20 x 9.8 / √3  N

Therefore the answer is Option (2):  20 x 9.8 / √3  N

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