a mass m rests on a horizontal surface. the co Efficient of friction between the mass and the surface is u. if the mass is pulled by a force F. the limiting friction between mass and the surface will be
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0
Answer:
F = mgu
The friction depends upon the reaction force ( opposite of weight) which is equal to mg .
The coefficient of friction is added in the equation to equalise the proportionality
Answered by
10
Answer:
μ[mg – (P/2)]
Explanation:
Limiting frictional force = F = μN
P sin θ + N = mg
P sin 30 + N = mg
mg – (P / 2) = N
hence F = μ[mg – (P / 2)]
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