Question

A mass m suspended from a spring oscillates with frequency 400 hz what will be the frequency of mass 4m

Answer 1

The angular frequency of oscillation, ω, is given by

ω = √(K/M) radians per second

where K is force constant of the spring and M is the suspended mass. Here, K = 120 N/m and M=0.3 kg. Therefore

ω = √(120/0.3)=√400 = 20 radians per second.