Question

A mass of 0.5 kg moving with a speed of 1.5 m/s
on a horizontal smooth surface, collides with a
nearly weightless spring of force constant
k = 50 N/m. The maximum compression of the
spring would be diagram)
(a) 0.5 m (b) 0.15 m
(c) 0.12 m (d) 1.5 m

Answer 1

Answer:

By the law of conservation of energy. Kinetic energy of mass = energy stored in spring 

21mv2=21kx2

x2=kmv2

The maximum compression of the spring

x=kmv2

x=500.5×1.5×1.5=0.15m

Answer 2

Answer:

kinetic energy of body = potential energy of spring

Explanation:

1\2mv2 = 1\2kx2

0.5*1.5*1.5 = 50*x2

x2= 0.225

x=0.15