A mass of 0.8kg at the end of a rope 0.5m long is whirled round in a horizontal circle at an angular speed of 10rad/s. Calculate the angular momentum of the whirled
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Answer:
2 kgm/sec
Explanation:
given
mass= 0.8kg
radius of circular path = 0.5m
angular velocity (w)= 10 rad/sec
angular momentum = m(rw)r
= 0.8×(0.5×10)×0.5
= 2 kgm/sec
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