Question

A mass of 1.48kg of fecl3 contains how many formula units

Answer 1

The number of formula units of iron (III) chloride are $5.494\times 10^{24}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of iron (III) chloride = 1.48 kg = 1480 g   (Conversion factor:  1 kg = 1000 g)

Molar mass of iron (III) chloride = 162.2 g/mol

Putting values in above equation, we get:

$\text{Moles of iron (III) chloride}=\frac{1480g}{162.2g/mol}=9.124mol$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of formula units

So, 9.124 moles of iron (III) chloride will contain = $(9.124\times 6.022\times 10^{23})=5.494\times 10^{24}$ number of formula units

Learn more about formula units:

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