A mass of 1 kg is seperated from another mass 1g by a distance of 1 cm. How many gram weight force exits b/w them
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Answer: 6.67×10^−11 N
Explanation:
m1 =m2 =1 kg, r=1 m
Force of gravitation F= Gm1 m2 /r²
F= 6.67×10^−11 ×1×1 /1² = 6.67×10^−11 N
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